Postby **ucim** » Tue Feb 13, 2018 2:17 am UTC

It's a hint. Take a look at your original equation and see if you recognize parts of it there, where you can substitute them. That may simplify the equation.

Also, look for symmetries - a set of solutions where a=b. (Check also for a = -b, since (-b)^{2} = b^{2}) Note - there may not be any.

Then look for solutions where a=kb. Simply substitute kb for a, reducing the number of variables (k is a constant). If there are solutions of that form, you should be able to figure out what k must be.

Then look for solutions where a=0 or b=0.

Hope that gets you started.

Jose

Order of the Sillies, Honoris Causam - bestowed by charlie_grumbles on NP 859 * OTTscar winner: Wordsmith - bestowed by yappobiscuts and the OTT on NP 1832 *

Ecclesiastical Calendar of the Order of the Holy Contradiction * Heartfelt thanks from addams and from me - you really made a difference.